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((1)/(8))^(3x)*64^(2x+1)=4
We move all terms to the left:
((1)/(8))^(3x)*64^(2x+1)-(4)=0
Domain of the equation: 8)^3x*64^(2x+1)!=0We add all the numbers together, and all the variables
x∈R
(+1/8)^3x*64^(2x+1)-4=0
We multiply all the terms by the denominator
(+1-4*8)^3x*64^(2x+1)=0
We add all the numbers together, and all the variables
(-31)^3x*64^(2x+1)=0
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